(3x-15)/(x^2-5x)=0

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Solution for (3x-15)/(x^2-5x)=0 equation: 


D( x )

x^2-(5*x) = 0

x^2-(5*x) = 0

x^2-(5*x) = 0

x^2-5*x = 0

x^2-5*x = 0

DELTA = (-5)^2-(0*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+5)/(1*2) or x = (5-25^(1/2))/(1*2)

x = 5 or x = 0

x in (-oo:0) U (0:5) U (5:+oo)

(3*x-15)/(x^2-(5*x)) = 0

(3*x-15)/(x^2-5*x) = 0

x^2-5*x = 0

x*(x-5) = 0

x-5 = 0 // + 5

x = 5

x*(x-5) = 0

(3*x-15)/(x*(x-5)) = 0

3*x-15 = 0 // + 15

3*x = 15 // : 3

x = 15/3

x = 5

x in { 5} 

x belongs to the empty set

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